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18x^2-61x=62
We move all terms to the left:
18x^2-61x-(62)=0
a = 18; b = -61; c = -62;
Δ = b2-4ac
Δ = -612-4·18·(-62)
Δ = 8185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-\sqrt{8185}}{2*18}=\frac{61-\sqrt{8185}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+\sqrt{8185}}{2*18}=\frac{61+\sqrt{8185}}{36} $
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